Q(x)=2x^2-5x+7

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Solution for Q(x)=2x^2-5x+7 equation: 



(Q)=2Q^2-5Q+7

We move all terms to the left:

(Q)-(2Q^2-5Q+7)=0

We get rid of parentheses

-2Q^2+Q+5Q-7=0

We add all the numbers together, and all the variables

-2Q^2+6Q-7=0

a = -2; b = 6; c = -7;
Δ = b2-4ac
Δ = 62-4·(-2)·(-7)
Δ = -20
Delta is less than zero, so there is no solution for the equation

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